X^2-22x+121=4

Solution for X^2-22x+121=4 equation:

X^2-22X+121=4

We move all terms to the left:

X^2-22X+121-(4)=0

We add all the numbers together, and all the variables

X^2-22X+117=0

a = 1; b = -22; c = +117;
Δ = b2-4ac
Δ = -222-4·1·117
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-4}{2*1}=\frac{18}{2}
=9
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+4}{2*1}=\frac{26}{2}
=13
$